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20x^2+5x-750=0
a = 20; b = 5; c = -750;
Δ = b2-4ac
Δ = 52-4·20·(-750)
Δ = 60025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{60025}=245$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-245}{2*20}=\frac{-250}{40} =-6+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+245}{2*20}=\frac{240}{40} =6 $
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